Matheminate
TopicsProgressWorksheetsGamesToolsAbout
Loading math...
TopicsAboutPrivacyTermsContact

© 2026 Matheminate. All rights reserved.

← Back to the ladder

Learn: Surface Area & Volume

A quick, calm intro — then you choose when to climb.

The idea

Surface area is the wrapping paper — every outside face, in square units. Volume is the filling — everything inside, in cubic units. A cylinder is two circles plus one curved rectangle: SA = 2πr² + 2πrh, and V = πr²h — the base circle stacked up.

Surface Area = wrap

Outside paper covering the shape (cm²)

Volume = fill

Inside space the shape holds (cm³)

Surface Area

unit: cm²

A cylinder unwraps into 2 circles + 1 rectangle.

Cylinder

rh

Unwrap (net)

2 circlescurved sidewidth = 2πrheight = h

Build the formula

1) Two ends: 2πr22\pi r^{2}2πr2
2) Side rectangle: (2πr)⋅h(2\pi r)\cdot h(2πr)⋅h
SA=2πr2+2πrhSA = 2\pi r^{2} + 2\pi r hSA=2πr2+2πrh

Volume

unit: cm³

Volume is the base circle stacked up to height hhh.

hbase area = πr²stack up

Build the formula

1) Base area: πr2\pi r^{2}πr2
2) Times height: ×h\times h×h
V=πr2hV = \pi r^{2} hV=πr2h

Memory check

Wrap paper → Surface Area → cm2cm^{2}cm2
Filling inside → Volume → cm3cm^{3}cm3

Surface Area = wrap

All outside faces added together (cm²)

Volume = fill

How much space is inside (cm³)

Cuboid (Box)

lwh
SA: SA=2(lw+lh+wh)SA = 2(lw + lh + wh)SA=2(lw+lh+wh)
V: V=lwhV = lwhV=lwh

Cube

s
SA: SA=6s2SA = 6s^{2}SA=6s2
V: V=s3V = s^{3}V=s3

Cylinder

rh
SA: SA=2πr2+2πrhSA = 2\pi r^{2} + 2\pi r hSA=2πr2+2πrh
V: V=πr2hV = \pi r^{2} hV=πr2h

Cone

hrl
SA: SA=πr2+πrlSA = \pi r^{2} + \pi r lSA=πr2+πrl
V: V=13πr2hV = \tfrac{1}{3}\pi r^{2} hV=31​πr2h

l = slant height

Sphere

r
SA: SA=4πr2SA = 4\pi r^{2}SA=4πr2
V: V=43πr3V = \tfrac{4}{3}\pi r^{3}V=34​πr3

Quick memory

  • If the question says wrap / paint / cover → Surface Area (cm2cm^{2}cm2)
  • If the question says fill / capacity / how much inside → Volume (cm3cm^{3}cm3)
  • For cylinder/cone/sphere, check whether you were given r or diameter first.

Worked example

Every step explained — why we do it, and what happens.

  1. 1
    V=πr2h=227×72×10V = \pi r^2 h = \frac{22}{7} \times 7^2 \times 10V=πr2h=722​×72×10

    Why: The base is a circle of area πr²; stacking h copies of it fills the cylinder.

    What happens: Volume = base circle × height.

  2. 2
    =154×10=1540 cm3= 154 \times 10 = 1540 \text{ cm}^3=154×10=1540 cm3

    Why: (22/7) × 49 = 154 — the base circle of a radius-7 cylinder.

    What happens: V = 1540 cm³ — the filling, in cubes.

  3. 3
    SA=2πr2+2πrh=2πr(r+h)SA = 2\pi r^2 + 2\pi r h = 2\pi r (r + h)SA=2πr2+2πrh=2πr(r+h)

    Why: Two circular ends (2πr²) plus the curved side, which unrolls into a rectangle: width 2πr (the rim), height h.

    What happens: Surface area = 2πr(r + h) — one tidy formula.

  4. 4
    =44×17=748 cm2= 44 \times 17 = 748 \text{ cm}^2=44×17=748 cm2

    Why: 2πr with r = 7 is 44 — the rim of the base circle; r + h = 17.

    What happens: SA = 748 cm² — the paper, in squares. Cubes fill, squares wrap; a wrong unit means a wrong formula.

Real-world example

A bakery sells cakes in cylindrical tins, radius 7 cm and height 10 cm (use π = 22/7). The cake fills the whole tin — how much cake is that? And how much gift wrap covers the whole tin — top, curved side and bottom?

  1. 1
    V=πr2hV = \pi r^2 hV=πr2h

    Why: The cake fills the tin — that is volume: base circle × height.

    What happens: V = (22/7) × 7² × 10.

  2. 2
    =154×10=1540 cm3= 154 \times 10 = 1540 \text{ cm}^3=154×10=1540 cm3

    Why: Base area 154 cm² (radius 7), times 10 cm of height.

    What happens: 1540 cm³ of cake.

  3. 3
    Trap: wrap =πr2h=1540 cm2 ?\text{Trap: wrap } = \pi r^2 h = 1540 \text{ cm}^2\,?Trap: wrap =πr2h=1540 cm2?

    Why: The glitch: using the volume formula for the paper. Gift wrap covers the OUTSIDE — every face — so it must be surface area, in square units.

    What happens: 1540 cm² would be the volume in disguise — wrong formula, wrong unit.

  4. 4
    SA=2πr(r+h)=44×17=748 cm2SA = 2\pi r (r + h) = 44 \times 17 = 748 \text{ cm}^2SA=2πr(r+h)=44×17=748 cm2

    Why: Two ends (2πr²) plus the curved side (2πrh) — factor 2πr; with r = 7 that is 44, and r + h = 17.

    What happens: 748 cm² of gift wrap.

  5. 5
    748 cm2≠1540 cm3748 \text{ cm}^2 \ne 1540 \text{ cm}^3748 cm2=1540 cm3

    Why: The check: squares versus cubes. 1540 fills the tin, 748 wraps it — different jobs, different formulas, different units.

    What happens: V = 1540 cm³, SA = 748 cm² ✓

Common glitch

Two classic glitches:

1.Using the diameter as the radius

Wrong:A cylinder with diameter 14 has r = 14 — the diameter is just a bigger radius

Right:Halve it first: diameter 14 → r = 7. Every formula is built on r, so one wrong r doubles every answer.

2.Volume for the paper, area for the filling

Wrong:πr²h and 2πr² + 2πrh are interchangeable — pick whichever looks nicer

Right:Filling → V = πr²h (cubes). Paper → SA = 2πr² + 2πrh (squares). The unit of your answer tells you which formula you used.

Try a related calculator

  • Volume and Surface Area Calculator — Calculate volume and surface area for common solids.
  • Unit Converter — Convert dimensions to consistent units before calculating.

Next up: Probability →

Keep the climb going with the next topic.

You've got the concept! Let's lock it in with practice.

Start Warm-Up Level →Back to Ladder

Learning is optional — the ladder is always open.