Matheminate

Inequalities & Absolute Value Practice

Solve linear and compound inequalities, flip signs with negative numbers, and work with absolute value equations and intervals.

Open this practice ladder →Learn Inequalities & Absolute Value

What an inequality actually says

An inequality compares two amounts instead of declaring them equal, so its answer is a range rather than one value. To say x is less than 4 is to describe every number below 4 at once. Solving means narrowing that range until the unknown stands alone on one side.

Four symbols carry the whole topic. < and > exclude their endpoint; ≤ and ≥ include it. On a number line that difference becomes an open circle or a filled one, and a mark in the wrong style costs a mark even when the algebra is right. The steps mirror those for an equation, with one exception: multiplying or dividing by a negative number turns the symbol round.

An answer is written as a range, such as x < 4, and read back as a sentence: any number smaller than four. Testing one value inside the range and one outside is the quickest check that the symbol points the right way, and it catches a reversed sign before the page is finished. For x < 4, try 0 as an inside value and 5 as an outside value. Substitute each into the original inequality rather than relying only on the final line. This quick check also helps with word problems, where phrases such as "at most" include the boundary but "less than" does not.

What this ladder covers

Six stops carry the ladder from reading symbols to two-sided inequalities.

Worked examples

Solve x + 3 < 7. Subtract 3 from both sides: x < 4. Every number below 4 works, including 3.9 and −10, and the boundary 4 does not.

Solve 5x > 20. Divide both sides by 5: x > 4. The symbol stays as it was, because 5 is positive and dividing by it does not change the order of the two sides.

Solve −2x > 8. Divide both sides by −2 and flip the symbol: x < −4. Check with −5: −2 × −5 = 10, and 10 is greater than 8, so −5 belongs in the answer.

Solve 3 ≤ x + 1 ≤ 7. Subtract 1 from all three parts: 2 ≤ x ≤ 6. The middle part is worked on, not the outer two, so the range keeps its two limits.

Solve 2x − 1 ≥ 9. Add 1 to both sides to get 2x ≥ 10, then divide by 2: x ≥ 5. Two moves, and the symbol is untouched because both divisors were positive.

Mistakes worth watching for

One rule about negatives accounts for most of the slips on this page.

How the ladder works

This ladder has six stops, the first a Warm-Up of five questions and the last a set of eight or nine. Clear a stop with 80% of first attempts right; nothing is locked, and each retry builds a fresh set.

Practice Inequalities & Absolute Value

Keep going

Print a set of inequalities with the inequalities worksheet generator, see the shaded region on screen with the graphing calculator, or move to linear equations, where the same balance method solves for an exact value.

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