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Learn: Inequalities & Absolute Value

Review the key ideas, then practise whenever you’re ready.

The idea

An equation says two sides are equal (x=5x = 5x=5). An inequality says one side is bigger or smaller (x>5x > 5x>5 or x≤5x \le 5x≤5) - so instead of a single answer, you get a whole zone of answers on the number line. Solve it with the exact same balance moves as a linear equation, plus ONE golden rule when dividing by a negative.

The three rules you need:

  1. 1

    Open circle vs Solid dot - x>2x > 2x>2 excludes 222 (smallest integer is 333); x≥2x \ge 2x≥2 includes 222 (smallest integer is 222).

  2. 2

    The Negative Flip Rule - multiplying or dividing both sides by a NEGATIVE number flips <<< to >>> and ≤\le≤ to ≥\ge≥.

  3. 3

    Sandwich & Absolute Value - in 1≤2x+3<91 \le 2x + 3 < 91≤2x+3<9, do each move to all three parts. ∣x−c∣|x - c|∣x−c∣ means distance from ccc.

Quick memory tips

  • Alligator rule: the mouth of <<< or >>> always opens toward the BIGGER side
  • Adding or subtracting NEVER flips the sign - only multiplying or dividing by a negative does
  • Quick check: test an easy number like x=0x = 0x=0 in the original inequality to confirm your arrow direction

Interactive Inequality Number-Line Explorer

Tap each rule to see how the circle and arrow behave on the number line.

Open circle ○ - boundary NOT included
-4-3-2-10123452 excluded (○)
x>2⇒smallest integer is 3x > 2 \quad\Rightarrow\quad \text{smallest integer is } 3x>2⇒smallest integer is 3

2 is the fence post, not part of the yard! The first whole number past 2 is 3.

Use an open circle ○ for < or >. Because there is no “equals” line underneath, the number 2 itself does not count.

See Why Multiplying by −1 Flips the Sign

On the right side of zero, 5 is further right than 2 (2<52 < 52<5). When you multiply by −1-1−1, everything mirrors across zero - now −2 is further right than −5 (−2>−5-2 > -5−2>−5)!

Before: 2<52 < 52<5 (true)
Times −1-1−1: −2>−5-2 > -5−2>−5 (sign MUST flip!)

Worked example

Every step explained - why we do it, and what happens.

  1. 1
    −2x+3≤11-2x + 3 \le 11−2x+3≤11

    Why: Read it in plain words: “negative 2 times x, plus 3, is at most 11.” Unwrap x step by step just like a balanced equation.

    What happens: Spot the −2 attached to x - that warns us we will divide by a negative at the end.

  2. 2
    −2x+3−3≤11−3-2x + 3 - 3 \le 11 - 3−2x+3−3≤11−3

    Why: Undo the “+ 3” first by subtracting 3 from both sides. Subtracting never flips the inequality sign.

    What happens: The +3 and −3 cancel on the left, and ≤ stays pointing the same way.

  3. 3
    −2x≤8-2x \le 8−2x≤8

    11 − 3 = 8, leaving −2x ≤ 8.

  4. 4
    −2x−2≥8−2\frac{-2x}{-2} \ge \frac{8}{-2}−2−2x​≥−28​

    Why: Divide both sides by −2 to get x alone. Because we divide by a NEGATIVE number, flip ≤ into ≥!

    What happens: The left side becomes x, and the inequality arrow reverses direction.

  5. 5
    x≥−4x \ge -4x≥−4

    Why: 8 ÷ (−2) = −4. Since ≥ means “greater than or equal to”, −4 itself is included.

    What happens: Every number from −4 upward works, so the smallest integer solution is −4.

  6. 6
    −2(0)+3=3≤11-2(0) + 3 = 3 \le 11−2(0)+3=3≤11

    Why: The check: pick an easy number that obeys x ≥ −4, such as x = 0, and test it in the original inequality.

    What happens: 3 ≤ 11 is true ✓ - the flipped arrow is right.

Absolute Value & Sandwich Inequalities (Optional Toolbox)

How to handle ∣x−c∣|x - c|∣x−c∣ bars and three-part inequalities when you reach the higher levels.

Levels 4–6

Absolute Value ∣x−1∣≤3|x - 1| \le 3∣x−1∣≤3 Means “Distance from 1 is at most 3”

Stand at 1 on the number line. Walk 3 steps left to −2 and 3 steps right to 4:

-3-2-1012345−3 steps+3 steps

1. Absolute Value Equation

∣x−1∣=3|x - 1| = 3∣x−1∣=3

Splits into two cases: x−1=3x - 1 = 3x−1=3 (x=4x = 4x=4) or x−1=−3x - 1 = -3x−1=−3 (x=−2x = -2x=−2).

2. Absolute Value Inequality

∣x−1∣≤3|x - 1| \le 3∣x−1∣≤3

Unpacks into a sandwich: −3≤x−1≤3-3 \le x - 1 \le 3−3≤x−1≤3, so −2≤x≤4-2 \le x \le 4−2≤x≤4.

3. Counting Integers in a Range

Count=Last−First+1\text{Count} = \text{Last} - \text{First} + 1Count=Last−First+1

From −2-2−2 to 444 inclusive: 4−(−2)+1=74 - (-2) + 1 = 74−(−2)+1=7 integers in total. Always add +1+1+1 so you count both endpoints!

Real-world example

A courier van charges a 10-coin flat pickup fee plus 4 coins for every box you send. You have 38 coins in your pocket. What is the largest whole number of boxes you can ship?

  1. 1
    4b+10≤384b + 10 \le 384b+10≤38

    Why: Let b be the number of boxes. 4 coins per box (4b) plus the 10-coin fee must be at most 38 coins (≤).

    What happens: The story becomes a two-step inequality.

  2. 2
    4b≤38−10=284b \le 38 - 10 = 284b≤38−10=28

    Why: Subtract the 10-coin flat fee from both sides first.

    What happens: You have at most 28 coins left for the boxes themselves.

  3. 3
    b≤28÷4=7b \le 28 \div 4 = 7b≤28÷4=7

    Why: Divide both sides by +4. Since +4 is positive, the ≤ sign does not flip.

    What happens: You can ship at most 7 boxes.

  4. 4
    Trap: 8 boxes⇒4(8)+10=42>38\text{Trap: } 8 \text{ boxes} \Rightarrow 4(8) + 10 = 42 > 38Trap: 8 boxes⇒4(8)+10=42>38

    Why: The glitch: rounding up or guessing 8 boxes costs 42 coins, which goes over your 38-coin budget.

    What happens: 8 boxes is too expensive - ≤ 7 is a hard ceiling.

  5. 5
    4(7)+10=28+10=384(7) + 10 = 28 + 10 = 384(7)+10=28+10=38

    Why: The check: 7 boxes cost 28 + 10 = 38 coins, which fits your 38-coin budget with 0 left over.

    What happens: Maximum = 7 boxes ✓.

Common glitch

Three classic traps to watch out for:

1.Forgetting to flip the sign when dividing by a negative

Wrong:−2x≤8⇒x≤−4-2x \le 8 \Rightarrow x \le -4−2x≤8⇒x≤−4 - testing x=−5x = -5x=−5 gives −2(−5)=10-2(-5) = 10−2(−5)=10, which is NOT ≤8\le 8≤8

Right:Dividing by −2-2−2 flips ≤\le≤ into ≥\ge≥: x≥−4x \ge -4x≥−4.

2.Flipping the sign just because the right side is negative

Wrong:2x≤−8⇒x≥−42x \le -8 \Rightarrow x \ge -42x≤−8⇒x≥−4 - flipping even though you divided by positive +2+2+2

Right:Only look at the number you divide BY. Dividing by +2+2+2 keeps the sign: x≤−4x \le -4x≤−4.

3.Confusing <<< (strict) with ≤\le≤ (inclusive)

Wrong:Saying the smallest integer that satisfies x>5x > 5x>5 is 555

Right:x>5x > 5x>5 has an open circle at 555 (555 is not allowed), so the smallest integer is 666.

Try a related calculator

  • Linear Equation Solver - Check the boundary equation before applying the inequality sign.
  • Linear & Quadratic Graphing Calculator - Plot linear expressions to see where outputs sit above or below a boundary.

Next up: Polynomials & Algebraic Identities →

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