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Learn: Surds & Advanced Exponents

Review the key ideas, then practise whenever you’re ready.

The idea

A square root is the non-negative number that squares to give the number under the root: √25 = 5. A surd is an irrational root, such as √3. First review powers, then see how they connect to roots.

Key ideas

  1. 1

    Powers with the same base - When multiplying powers with the same base, add the exponents. When dividing, subtract them: am×an=am+na^m \times a^n=a^{m+n}am×an=am+n and am÷an=am−na^m \div a^n=a^{m-n}am÷an=am−n, where a≠0a\ne0a=0. A power raised to another power multiplies the exponents: (am)n=amn(a^m)^n=a^{mn}(am)n=amn.

  2. 2

    Powers over multiplication and division - A power applies to each factor: (ab)n=anbn(ab)^n=a^n b^n(ab)n=anbn and (a/b)n=an/bn(a/b)^n=a^n/b^n(a/b)n=an/bn, where b≠0b\ne0b=0. It does not distribute over addition: (2+3)2=25(2+3)^2=25(2+3)2=25, but 22+32=132^2+3^2=1322+32=13.

  3. 3

    Zero and negative exponents - For a≠0a\ne0a=0, a0=1a^0=1a0=1 and a−n=1/ana^{-n}=1/a^na−n=1/an. A negative exponent means take the reciprocal; it does not make the value negative.

  4. 4

    Roots and surds - To simplify a square root, factor out a perfect square: 75=25×3=53\sqrt{75}=\sqrt{25 \times 3}=5\sqrt{3}75​=25×3​=53​, because 25=5\sqrt{25}=525​=5.

  5. 5

    Multiplying and dividing roots - For a,b≥0a,b\ge0a,b≥0, a b=ab\sqrt a\,\sqrt b=\sqrt{ab}a​b​=ab​. Also, ab=ab\frac{\sqrt a}{\sqrt b}=\sqrt{\frac ab}b​a​​=ba​​ when b>0b>0b>0. Roots do not generally distribute over addition: 9+16≠9+16\sqrt{9+16}\ne\sqrt9+\sqrt{16}9+16​=9​+16​, since 5≠75\ne75=7.

  6. 6

    Fractional exponents - For a>0a>0a>0 and positive integers m,nm,nm,n, am/n=amna^{m/n}=\sqrt[n]{a^m}am/n=nam​. The denominator gives the root; the numerator gives the power. For example, 82/3=(83)2=48^{2/3}=(\sqrt[3]{8})^2=482/3=(38​)2=4.

  7. 7

    Combining surds - Simplify each root first. Then combine terms with the same root: 50+18=52+32=82\sqrt{50}+\sqrt{18}=5\sqrt2+3\sqrt2=8\sqrt250​+18​=52​+32​=82​.

  8. 8

    Rationalise denominators - Multiply the numerator and denominator by the same non-zero expression, so the fraction stays equal. For a two-term denominator, use its conjugate: the same terms with the sign changed, such as 3−73-\sqrt73−7​ and 3+73+\sqrt73+7​.

  9. 9

    Equations with powers and roots - Use exponent rules to solve equations with matching bases. If you square both sides, check your answer in the original equation.

Interactive Surds & Fractional Power Explorer

Pick a tab to see how roots and fractional powers work.

Write 75=25×3\sqrt{75} = \sqrt{25 \times 3}75​=25×3​. Only 25 = 5² is a perfect square, so 25=5\sqrt{25} = 525​=5 steps outside the root. The 3 has no square partner, so it stays inside.

25(5 × 5)×3(stays in)53
75=25×3=25×3=53\sqrt{75} = \sqrt{25 \times 3} = \sqrt{25}\times\sqrt{3} = 5\sqrt{3}75​=25×3​=25​×3​=53​

Perfect squares to hunt for: 4, 9, 16, 25, 36, 49, 64, 81, 100

Worked example

Every step explained - why we do it, and what happens.

  1. 1
    50+18\sqrt{50} + \sqrt{18}50​+18​

    Why: We cannot combine these roots yet because their root parts differ. Simplify each one first by finding a perfect-square factor.

    What happens: Look for a perfect square that divides both 50 and 18.

  2. 2
    =25×2+9×2= \sqrt{25 \times 2} + \sqrt{9 \times 2}=25×2​+9×2​

    Why: Write each number as a perfect square times 2: 50 = 25 × 2 and 18 = 9 × 2.

    What happens: Now each root has a perfect-square factor we can simplify.

  3. 3
    =25⋅2+9⋅2= \sqrt{25} \cdot \sqrt{2} + \sqrt{9} \cdot \sqrt{2}=25​⋅2​+9​⋅2​

    Why: For non-negative factors, the square root of a product equals the product of the square roots.

    What happens: This lets us take the square roots of 25, 9, and 2 separately.

  4. 4
    =52+32= 5\sqrt{2} + 3\sqrt{2}=52​+32​

    Both terms now have the same root part, √2.

  5. 5
    =(5+3)2=82= (5 + 3)\sqrt{2} = 8\sqrt{2}=(5+3)2​=82​

    Why: Add the coefficients (5 + 3 = 8) and keep √2 unchanged, just as 5x + 3x = 8x.

    What happens: The simplified result is 8√2.

Rationalizing Denominators & Matching Bases (Optional Toolbox)

How to clear square roots from the bottom of a fraction and solve exponential equations like 4x+1=824^{x+1} = 8^24x+1=82.

Optional - Extension Level

1. Conjugate Trick for Denominators

To clear 3−73 - \sqrt{7}3−7​ from the denominator in the fraction shown below, multiply the numerator and denominator by its conjugate 3+73 + \sqrt{7}3+7​. The denominator becomes 32−(7)2=9−7=23^2 - (\sqrt{7})^2 = 9 - 7 = 232−(7​)2=9−7=2 because (a−b)(a+b)=a2−b2(a-b)(a+b)=a^2-b^2(a−b)(a+b)=a2−b2 (the root is gone):

63−7×3+73+7=6(3+7)2=3(3+7)=9+37\frac{6}{3 - \sqrt{7}} \times \frac{3 + \sqrt{7}}{3 + \sqrt{7}} = \frac{6(3 + \sqrt{7})}{2} = 3(3 + \sqrt{7}) = 9 + 3\sqrt{7}3−7​6​×3+7​3+7​​=26(3+7​)​=3(3+7​)=9+37​

2. Matching Bases for Power Equations

In 4x+1=824^{x+1} = 8^24x+1=82, spot that 4 = 2² and 8 = 2³. Rewrite both sides with base 2, then equate the exponents:

(22)x+1=(23)2  ⇒  2(x+1)=6  ⇒  x=2(2^2)^{x+1} = (2^3)^2 \;\Rightarrow\; 2(x+1) = 6 \;\Rightarrow\; x = 2(22)x+1=(23)2⇒2(x+1)=6⇒x=2

Real-world example

Two square skylights sit side by side along a straight roof beam. Their areas are 75 m² and 12 m². What is their combined width in simplest surd form?

  1. 1
    W=75 m+12 mW = \sqrt{75}\,\text{m} + \sqrt{12}\,\text{m}W=75​m+12​m

    Why: The side length of a square is the square root of its area.

    What happens: We need to simplify √75 and √12 and add them.

  2. 2
    75=25×3=53 m\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3} \text{ m}75​=25×3​=53​ m

    Why: Since 75 = 25 × 3 and √25 = 5, the side length is 5√3 m.

    What happens: The large skylight is 5√3 m wide.

  3. 3
    12=4×3=23 m\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3} \text{ m}12​=4×3​=23​ m

    Why: Since 12 = 4 × 3 and √4 = 2, the side length is 2√3 m.

    What happens: The small skylight is 2√3 m wide.

  4. 4
    Trap: 75+12=87 ?\text{Trap: } \sqrt{75} + \sqrt{12} = \sqrt{87}\,?Trap: 75​+12​=87​?

    Why: You cannot add the numbers inside separate square roots. √87 is about 9.33 m, but the correct total is about 12.12 m.

    What happens: Simplify each surd first, then add the matching root parts.

  5. 5
    53+23=73 m(k=7)5\sqrt{3} + 2\sqrt{3} = 7\sqrt{3} \text{ m} \quad (k = 7)53​+23​=73​ m(k=7)

    Why: Both terms have √3, so add their coefficients: 5 + 2 = 7.

    What happens: The total width is 7√3 m.

Common glitch

A few mistakes to watch for:

1.Adding numbers directly under separate square roots

Wrong:9+16=25=5\sqrt{9} + \sqrt{16} = \sqrt{25} = 59​+16​=25​=5 - check it: 3+4=73 + 4 = 73+4=7, not 555!

Right:Simplify each root first, and only add the outside numbers when the root part matches.

2.Mixing up the power and the root in a fractional exponent

Wrong:Reading 82/38^{2/3}82/3 as “square root of 838^383”

Right:The bottom number tells the root: 82/3=(83)2=22=48^{2/3} = (\sqrt[3]{8})^2 = 2^2 = 482/3=(38​)2=22=4.

3.Thinking a negative exponent makes the answer negative

Wrong:2−3=−82^{-3} = -82−3=−8 (thinking the negative sign makes the answer negative)

Right:A negative exponent means reciprocal, not a negative value: 2−3=123=182^{-3} = \frac{1}{2^3} = \frac{1}{8}2−3=231​=81​.

Try a related calculator

  • Prime Factorization Calculator - Factor a number into primes to spot every perfect-square pair under a root.
  • General Calculator - Check roots and powers with the scientific calculator keys.

Next up: Linear Equations →

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