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Learn: Pythagorean Theorem

A quick, calm intro — then you choose when to climb.

The idea

In a right triangle, the two shorter sides are the legs (a and b). The longest side — always opposite the right angle — is the hypotenuse (c).

The formula:

  1. 1

    Legs (a, b) — the two shorter sides that meet at the right angle

  2. 2

    Hypotenuse (c) — the longest side, always opposite the right angle

  3. abc
  4. 3

    Pythagoras — a2+b2=c2a^2 + b^2 = c^2a2+b2=c2 — square both legs, add the squares, take the square root

Quick memory tips

  • Only for right triangles — it fails on every other triangle
  • Do not add the legs first — square each leg first
  • Need a leg instead? Rearrange: a2=c2−b2a^2 = c^2 - b^2a2=c2−b2
  • 3-4-5 is the builder’s favourite: 9 + 16 = 25

Quick Memory Tips

  • Only for right triangles — it fails on every other triangle
  • Do not add the legs first — square each leg first
  • Need a leg instead? Rearrange: a2=c2−b2a^2 = c^2 - b^2a2=c2−b2
  • 3-4-5 is the builder's favourite: 9+16=259 + 16 = 259+16=25
a² = 9b² = 16c² = 25a = 3b = 4c = 5

The squares show areas, not side lengths.

Leg square:a2=32=9a^2 = 3^2 = 9a2=32=9
Leg square:b2=42=16b^2 = 4^2 = 16b2=42=16
Hypotenuse square:c2=52=25c^2 = 5^2 = 25c2=52=25
9+16=259 + 16 = 259+16=25
so 32+42=523^2 + 4^2 = 5^232+42=52
!Do not mix side and side². a=3a = 3a=3 is length, a2=9a^2 = 9a2=9 is area.

Worked example

Every step explained — why we do it, and what happens.

  1. 1
    32+42=c23^2 + 4^2 = c^232+42=c2

    Why: Square both legs first — do not add the legs first. The legs are the two shorter sides meeting at the right angle.

    What happens: 9 + 16 = c² — each leg squared.

  2. 2
    c2=9+16=25c^2 = 9 + 16 = 25c2=9+16=25

    Why: Add the squares of the legs: 3² = 9 and 4² = 16.

    What happens: c² = 25 — the hypotenuse squared.

  3. 3
    c=25=5c = \sqrt{25} = 5c=25​=5

    Why: Undo the square: take the square root of both sides.

    What happens: c = 5 ✓ — the hypotenuse.

Real-world example

A ladder leans against a wall: its foot is 3 m from the wall and the top reaches 4 m up the wall. How long is the ladder?

  1. 1
    32+42=c23^2 + 4^2 = c^232+42=c2

    Why: The ladder, the wall and the ground form a right triangle — the ladder is the hypotenuse, the longest side.

    What happens: Legs 3 m and 4 m, hypotenuse c.

  2. 2
    c2=9+16=25c^2 = 9 + 16 = 25c2=9+16=25

    Why: Square the legs and add: 3² = 9, 4² = 16 — metres squared.

    What happens: c² = 25 m².

  3. 3
    c=25=5 mc = \sqrt{25} = 5 \text{ m}c=25​=5 m

    Why: Root to undo the square: √25 = 5.

    What happens: The ladder is 5 m ✓

  4. 4
    Trap: 3+4=7 m\text{Trap: } 3 + 4 = 7 \text{ m}Trap: 3+4=7 m

    Why: The glitch: adding the legs BEFORE squaring. Do not add the legs first — square each leg first. 3 + 4 = 7 would give c = 7 m, but the ladder is 5 m.

    What happens: c = 5 m, not 7 m.

  5. 5
    Check: 32+42=9+16=25=52\text{Check: } 3^2 + 4^2 = 9 + 16 = 25 = 5^2Check: 32+42=9+16=25=52

    Why: Run the theorem backwards: 25 is 5², so the hypotenuse is 5. This is why 3-4-5 is a builder’s favourite triangle.

    What happens: 5 m ✓ — the theorem holds.

Common glitch

Two classic glitches:

1.Adding the legs before squaring

Wrong:3+4=73 + 4 = 73+4=7, so the hypotenuse is 7

Right:Square each leg first: 32+42=9+16=253^2 + 4^2 = 9 + 16 = 2532+42=9+16=25, then c=25=5c = \sqrt{25} = 5c=25​=5.

2.Forgetting the square root

Wrong:c2=25c^2 = 25c2=25, so c=25c = 25c=25

Right:Undo the square: c=25=5c = \sqrt{25} = 5c=25​=5.

Try a related calculator

  • Pythagorean Theorem Calculator — Find a missing side in a right triangle.
  • Trigonometry Calculator — Use an angle and side to find other right-triangle measurements.

Next up: Trigonometry (SOH CAH TOA) →

Keep the climb going with the next topic.

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