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Learn: Circles

A quick, calm intro — then you choose when to climb.

The idea

A circle has two main measurements — the rim and the inside. Two formulas, one job each.

The two formulas:

  1. 1

    Circumference — distance around the rim: C=2πrC = 2\pi rC=2πr — a length, in cm or m

  2. 2

    Area — space inside: A=πr2A = \pi r^2A=πr2 — a surface, in cm² or m²

  3. 3

    Read the question — rim or inside? Each formula answers exactly one of them

Quick memory tips

  • π≈227\pi \approx \frac{22}{7}π≈722​ — use it when the radius plays nicely (7, 70, 14…)
  • Square the radius FIRST: πr2\pi r^2πr2 means π×(r×r)\pi \times (r \times r)π×(r×r)
  • Units tell the truth: cm = rim, cm² = inside
Circumferenceunit: cm

The distance around the rim.

r↷
C=2πrC = 2\pi rC=2πr
Areaunit: cm²

The space inside the circle.

r
A=πr2A = \pi r^{2}A=πr2
Radius vs Diameter

The radius is half the diameter — don't mix them up.

diameter (d)radius (r)
r=d2ord=2rr = \frac{d}{2} \quad \text{or} \quad d = 2rr=2d​ord=2r

Example: diameter = 14 → radius = 14 ÷ 2 = 7 (not 14!)

Blue = around the rim (circumference) · Green = inside the circle (area) · Amber = radius vs diameter warning

Worked example

Every step explained — why we do it, and what happens.

  1. 1
    r=7 cmr = 7 \text{ cm}r=7 cm

    Why: The radius is the distance from the centre to the edge — half of the diameter.

    What happens: A circle with radius 7.

  2. 2
    C=2πr=2×227×7=44 cmC = 2\pi r = 2 \times \frac{22}{7} \times 7 = 44 \text{ cm}C=2πr=2×722​×7=44 cm

    Why: Circumference is the distance around the rim: 2πr. The 7 cancels the 7 in 22/7 nicely.

    What happens: 44 cm around.

  3. 3
    A=πr2=227×72=154 cm2A = \pi r^2 = \frac{22}{7} \times 7^2 = 154 \text{ cm}^2A=πr2=722​×72=154 cm2

    Why: Area is the space inside: πr². Square the radius FIRST (7² = 49), then multiply.

    What happens: 154 cm² inside.

  4. 4
    C=44 cm,A=154 cm2C = 44 \text{ cm}, \qquad A = 154 \text{ cm}^2C=44 cm,A=154 cm2

    Same radius, two different answers: 44 (around, cm) vs 154 (inside, cm²). The formula decides.

Real-world example

A circular picnic table has a radius of 70 cm. A cloth must cover the whole tabletop, and a ribbon must go around the rim. How much cloth, and how much ribbon?

  1. 1
    r=70 cmr = 70 \text{ cm}r=70 cm

    Why: The radius of the table is 70 cm — the same r in both formulas.

    What happens: Radius 70.

  2. 2
    A=227×702=227×4900=15400 cm2A = \frac{22}{7} \times 70^2 = \frac{22}{7} \times 4900 = 15400 \text{ cm}^2A=722​×702=722​×4900=15400 cm2

    Why: The cloth covers the top — that is the area: πr². 70² = 4900.

    What happens: 15400 cm² of cloth.

  3. 3
    C=2×227×70=440 cmC = 2 \times \frac{22}{7} \times 70 = 440 \text{ cm}C=2×722​×70=440 cm

    Why: The ribbon wraps the rim — that is the circumference: 2πr.

    What happens: 440 cm of ribbon.

  4. 4
    Trap: using A=2πr=2×227×70=440\text{Trap: using } A = 2\pi r = 2 \times \frac{22}{7} \times 70 = 440Trap: using A=2πr=2×722​×70=440

    Why: The glitch: swapping the formulas. That is the ribbon formula, not the cloth — 440 is the rim length in cm, not a surface at all. Cloth needs area: πr², in cm².

    What happens: 440 cm is a length (ribbon); the cloth needs 15400 cm².

  5. 5
    A=15400 cm2,C=440 cmA = 15400 \text{ cm}^2, \quad C = 440 \text{ cm}A=15400 cm2,C=440 cm

    Why: The check: same radius, rim and inside both computed — each formula did its own job.

    What happens: ✓ cloth 15400 cm², ribbon 440 cm.

Common glitch

Two classic glitches:

1.Swapping circumference and area

Wrong:Area = 2πr2\pi r2πr — using the rim formula for the inside

Right:Rim: C=2πrC = 2\pi rC=2πr. Inside: A=πr2A = \pi r^2A=πr2.

2.Using the diameter as the radius

Wrong:diameter = 14, so r=14r = 14r=14

Right:The radius is half the diameter: r=14÷2=7r = 14 \div 2 = 7r=14÷2=7.

Try a related calculator

  • Area and Perimeter Calculator — Calculate a circle’s circumference and area.

Next up: Pythagorean Theorem →

Keep the climb going with the next topic.

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